3d^(2/3)-d^(1/3)-4=0

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Solution for 3d^(2/3)-d^(1/3)-4=0 equation: 


d in (-oo:+oo)

3*d^(2/3)-d^(1/3)-4 = 0

t_1 = d^(1/3)

3*t_1^2-1*t_1^1-4 = 0

3*t_1^2-t_1-4 = 0

DELTA = (-1)^2-(-4*3*4)

DELTA = 49

DELTA > 0

t_1 = (49^(1/2)+1)/(2*3) or t_1 = (1-49^(1/2))/(2*3)

t_1 = 4/3 or t_1 = -1

t_1 = -1

d^(1/3)+1 = 0

1*d^(1/3) = -1 // : 1

d^(1/3) = -1

( -1 < 0 i 1/3 in (0:1) ) => d należy do O

t_1 = 4/3

d^(1/3)-4/3 = 0

1*d^(1/3) = 4/3 // : 1

d^(1/3) = 4/3

d^(1/3) = 4/3 // ^ 3

d = 64/27

d = 64/27

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